Răspunsuri

Cel mai inteligent răspuns!
2014-05-23T15:30:46+03:00
A) 4x²-4x+1+4(x²-2x+1)-(4x²-2x+6x-6)-(4x²+4x+1)<0
4x²-4x+1+4x²-8x+4-4x²-4x+6-4x²-4x-1<0

-18x+10<0⇒-18x<-10 inmultind cu -1⇒
x>10/18,x>5/9
x∈(5/9,+∞)
b)
3x²-x+4x²+12x+9<8x²+96x+x²-6x+9-2x²+79
reducand termenii asemenea avem
79x>79
x>1,x∈(1,+∞)
c)x²+8x+16+3x²-18<4x²+2x-18x-18
8x-2<-16x-18
24x<-16
x<-16/24
x<-4/6
x<-2/3
x∈(-∞,-2/3)

d)(x-1)/3-3(10x-7)/4>x+11/4
aducand la acelasi numitor avem
4x-4-9(10x-7)>12x+33
4x-4-90x+63-12x-33>0
-98x+26>0
-98x>-26 inmult cu -1
98x<26
x<26/98
x<13/49
x∈(-∞,13/49)
succes si mi-a facut placere sa te cunosc
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