1)Caculati:
√3(√2+3√3) - 2√3(√3 - 2√2)=
2) Aflati ma si mg a numerelor :
a=6√3 si b=2√3
3)Calculati:
2
a)(3x+2)
2
b)(2√3+3)
c)(3√2-4)(3√2+4)
4)Descompuneti in factori primi:
a)3x(x-1)+4(x-1)
2
b)x +4+4
2
c)x +7x +12
5) Rezolvati ecuatiile :
2
a)x =36
2
b)(x-1) =16
2
c)(x+2)(x+1)-x +1=2(2x-1)

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Răspunsuri

Cel mai inteligent răspuns!
2014-05-22T22:16:53+03:00
1)⇒√6+3·3-2·3+2√6=3√6+3=3(√6+1)
2) Ma=(6√3+2√3)/2=8√3/2=4√3
6√3·2√3=12·3=36
Mg=√36=6
3a) (3x²+2)²=9x²+12x+4
X1=X2=-12/9
b) (2√3+3)²=4·3+6√3+9=21+6√3=3(7+2√3)
c) ⇒=9·2+12√2-12√2-16=18-16=2
5a)x²=36⇒   x1=√36=6
X2=-√36=-6
b)  ⇒x²-2x+1=16
x²-2x-15=0
(x-5)(x+3)=0
x-5=0⇒X1=5
x+3=0⇒X2=-3
c)⇒x²+x+2x+1-x²+1=4x-2
3x-4x=-2-2
-x=-4    ·(-1)
x=4
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