Răspunsuri

2014-05-22T00:15:26+03:00
2014-05-22T01:09:50+03:00
DE || AC=> ΔABC ~ ΔBDE=>AC\BE=CB\DB
 (INLOCUIM CE CUNOASTEM)
<=> 18/6=CB/DB <=>

DC=DB+CB=>DB=DC - CB<=>8-CB

<=>16/8=CB/8-CB (FACEM PRODUSUL MEZILOR SI AL EXTREMILOR= INMULTIM PE DIAGONALA)
<= >6CB=18(8-CB)
<=>6CB=18*8-18CB
<=>6CB=144-18CB
6CB+18CB=144=>24CB=144=>CB=144/24=>CB=6

A ΔABC=C1*C2/2, UNDE C1,C2 REPREZINTA CATETA 1 RESPECTIV CATETA 2
A ΔABC=BC*AC/2<=>A ΔABC=6*18/2=>A ΔABC=54