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2014-05-21T16:09:10+03:00
CH3COOH + NaOH ---> CH3COONa + H2O
cM=nr moli/volum=>nr moli acid = 0,02*0,2=0,004 moli CH3COOH
1 mol acid.......1 mol NaOH
0,004 moli acid........x moli NaOH         x = 0,004 moli NaOH
cM=nr moli/volum=>volum NaOH = 0,004/0,1=> volum NaOH = 0,04 litri = 40 ml
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